Number the red marbles 1 4 and the blue marbles 5 9.
A bag contains red and blue marbles two marbles are drawn without replacement.
Two marbles are drawn without replacement.
Then there are 4 possibilities for drawing the first red marble and 3 possibilities for drawing the second red marble.
P at least one red p rr or rb or br alternatively p at least one red 1 p no reds complementary events 1 p bb and so on.
B find probabilities for p bb p br p rb p ww p at least one red p exactly one red 3.
Two marbles are drawn simultaneously from the bag.
A bag contains 4 red marbles and 5 blue marbles.
Two marbles are drawn without replacement from a jar containing 4 black and 6 white marbles.
P both red p second is red.
On the other hand there are 9 choices for the first marble and 8.
A bag contains 3 white 4 black and 2 red marbles.
A bag contains 5 red and 3 blue marbles.
Determine the probability that at least one is red.
The probability of selecting a red marble and then a blue marble is 0 28.
A bag contains red and blue marbles.
A draw the tree diagram for the experiment.
Two marbles are drawn from the bag.
Can someone please point why my solution is wrong.
I disagree with the given answer frac29.
Two marbles are randomly drawn without replacement.
The probability of selecting a red marble on the first draw is 0 5.
Two marbles are drawn without replacement from an urn containing 4 red marbles 5 white marbles and 2 blue marbles.
Two marbles are drawn without replacement.
The first marble drawn is blue and the second is red.
If replacement is not allowed what is the probability that the second marble drawn will be red.
P both red frac binom22.
Drawing simultaneously is the same as sampling without.
Determine the probability that.