One worker pushes forward on the crate with a force of 270 n while the other pulls in the same direction with a force of 130 n using a rope connected to the crate.
A 100 kg crate sliding on the floor.
μ is the coefficeient of friction.
A 20 0 kg crate is at rest on a floor as shown in.
A f m 25n 100kg 0 25 m s 2.
Both forces are horizontal and the crate slides at a constant speed.
P m v 80kg x 2 5 m s 200 kg m s.
If a force of 250 n parallel to the floor is applied to the crate what s the magnitude of the force of static friction on the crate.
One worker pushes forward on the crate with a force of 380 n while the other worker pull in the same direction with a force of 350 n using a rope.
If a force of 250 n parallel to the floor is applied to this mass the magnitude of the force of static friction on the crate is 250 n.
Both forces are horizontal and the crate slides with a constant speed.
A crate of mass 100 kg rests on a horizontal floor.
Here s how to crack it the normal force on the object balances its weight so f n mg 100 kg 10 m s 2 1 000 n therefore f static friction max f f static max µ s f n 0 4 1 000 n 400 n.
Two workers are sliding a 100 kg crate across the floor.
What is the deceleration of the crate.
After t 0 second it acquires pure rolling motion as shown in figure.
Calculate the velocity of the centre of mass of the disc at t 0.
A uniform disc of mass and radius r is projected horizontally with velocity v c on a rough horizontal floor so that it starts off with a pure sliding motion at t 0.
What is the crate s coefficient of kinetic friction on the floor.
Two workers are sliding a 300 kg crate across the floor.
The coefficient of static friction is 0 4.
This is the maximum force that.
The maximum possible static friction force is µsn µsmg 0 4 100 10 400 n.
A 100 kg crate sliding on the floor is brought to a stop by a 25 n force.
The coefficient of static friction between the crate and floor is 0 700 and the coefficient of kinetic friction is 0 600.